(See added special bonus)
For the following problems, consider a semiconductor for which \(E_g = 1 eV, \quad kT=.025 eV\) and
\(D_c = 12 \times 10^{21} \frac{states}{eV*cm^3}, \quad B_c = 3 eV\)
\(D_v = 12 \times 10^{21} \frac{states}{eV*cm^3}, \quad B_v = 3 eV\).
(Assume that within each band the density of states is independent of E.)
Let's set our zero of energy at the top of the valence band.
Please mention any possible typos, confusing things etc. I noticed a number of autocorrect issues and mistakes in the last HW.
It will probably help to discuss a lot of this in the comments here. For example, how do the units work going from charge to electric field to potential? How does one end up with a potential in eV? (You may have to convert from cm to meters when you use surface charge to calculate electric field if epsilon_o is in Farads/meter.)
Solutions link:
https://drive.google.com/file/d/0B_GIlXrjJVn4V3AwV1lpR0M2Zms/view?usp=sharing
1. a) If this semiconductor is undoped, then what is the value of n at room temperature? What is the relationship between n and p? What is \(E_f\) for this un-doped case?
b) Suppose that this semiconductor is doped with 10^17 donors/cm^3. In that case we like to assume that each donor contributes one electron to the conduction band. What is \(E_f\) in this case?
c) extra credit: What do you think might be the rationale behind choosing \(12 \times 10^{21} \frac{states}{eV*cm^3}\) for the density of states? Why that value? (post here)
2. a) Plot the density of states as a function of energy from E from E = -4 eV to +4 eV.
b) Calculate n and p for \(E_f = 0.5 eV\).
c) Calculate n and p for \(E_f = 0.2 eV\).
d) Calculate n and p for \(E_f = 0.8 eV\).
e) Do a semi-log graph of n and p as a function of \(E_f\) for \(E_f\) in the range 0.1 to 0.9 eV. Can you use the approximate form of the Fermi function for this calculation?
3. For the same semiconductor, suppose you dope it with 10^17 donor atoms per cm^3. Then you get 10^17 electrons/cm^3 in the conduction band and 10^17 positively charged donor atoms/cm^3 embedded in the lattice.
a) What is the charge density associated with just the electrons in the conduction band (in coulombs/cm^3)?
b) What is the charge density associated with the positive ions (in coulombs/cm^3)?
c) What is the net charge density?
d) What would the net charge density be if all the electrons magically disappeared?
4. Consider a semiconductor as above. Suppose that it is doped with 10^17 donors for the half to the left of the plane x=0, and doped with 10^17 acceptors/cm^3 to the right of x=0. (The plane x=0 defines an interface between to two differently doped regions.) Suppose that within a distance \(x_d\) of the interface all the electrons in the conduction band from the left side cross over to the other side and fill up previously empty valance band states (holes) there.
a) For a particular value given of \(x_d\), (100 nm for example), plot the charge density as a function of x?
b) For the same given value of \(x_d\), what is the electric field at x= 0? (discuss/post here) What is the electric field as a function of x? (discuss here)
c) Using the relationship between electrical potential and electric field (or charge density) calculate the potential, V(x), as a function of x from x= -infinity to x=0 for the same given value of \(x_d\) (discuss here).
d) Plot the charge, electric field and potential as a function of x over a suitable range.
e) For \(x_d\) = 50 nm what is the change in electric potential from V(x= -infinity) to V(x=0)? (discuss)
f) For \(x_d\) = 100 nm what is the change in electric potential from V(x= -infinity) to V(x=0)? (discuss)
5. a) When \(E_f\) is independent of x, that represents an equilibrium state. What value of \(x_d\) would enable to bands to bend and shift by just the right amount to enable \(E_f\) to be independent of x?
b) Plot the conduction band edge and valence band edge as a function of x for this case.
6. Suppose the doping on each side is 10^18 cm^-3 instead of 10^17 cm^-3.
a) why might one guess that in that case the equilibrium value of \(x_d\) might be 10 times shorter than for the 10^17 case?
b) What is the actual equilibrium value of \(x_d\) for this case? Why is it not exactly 10 times smaller? (What additional factor influences x_d?)
7. Suppose the doping on each side is 10^16 cm^-3.
What is the equilibrium value of \(x_d\) for this case?
Note added: 8 and 9 are basically just sketches with a scale on the vertical axis (energy). No need to read them as anything more than that.
8. Now let's consider applying a voltage across the junction.
a) Plot Ef as a function of x for applied voltages of 0 and 0.2 V. What is it like? Discuss here? (You may assume the voltage drop takes place just over the junction region (the depleted region).
b) Plot the band edge energies as a function of x for applied voltages of 0 and 0.2 V.
9. How about applying a voltage across the junction in the other direction.
a) Plot Ef as a function of x for applied voltages of 0 and -0.2 V. What is it like? Discuss here? (You may assume the voltage drop takes place just over the junction region (the depleted region).
b) Plot the band edge energies as a function of x for applied voltages of 0 and -0.2 V.
c) Discuss these 3 cases? (-2, 0 and +2 V) How do they differ?
10. extra credit: a) For one of the n-p junctions you solved above, use your calculated value for \(E_c (x)\) for x less than zero to calculate n(x) as a function of x for x less than zero. Can you use the equation \(n(x) = KT D_c e^{-(E_c (x) - E_f)/kT}\)? Why or why not? (post here)
b) Graph n(x) as a function of x. Where/what is its maximum value?
c) Graph the product of the conduction electron density times the electric fields a function of x. Why would this be of possible interest? To what is it relevant? Where does its maximum value occur?
11. Special Bonus: \(n(x) e^2 \tau/m^*m\) multiplied time electric field has units of current per unit area. I think that if you use your expression for n(x) (from the previous problem) and multiply it time the electric field in the junction, which varies linearly with x, that correspond to a current associated with electrons accelerated by the electric field. Special bonus points to anyone who can calculate the peak value of that current in Coulombs/second (amperes) for a specific junction with an area of 1 cm^2, using m*=0.2 and \(\tau = 10^{-12}\) seconds. (Use the specific 10^17 doping case above. We want an actual number. Is it big, small, negligible, 10^-15 amps, 2 amps or what?)
Hints: One can separate out the term \( \mu= e \tau/m = e \tau c^2/(m^*m c^2)\). With mc^2 in eV and c in cm/s that can have units of \(cm^2/(Volt*seconds\). (The e turns eV into Volts...).
Does the maximum in this product occur about 1/5 of the way from -x_d to zero? That is, sort of near the edge where n(x) is not too small, but not right at the edge because that electric field is zero there?
Use \( instead of $$.
ReplyDeletethen use \) to end the latex phrase
ReplyDeleteyes. anytime a semiconductor is undoped you can assume that. I am not sure which approximation you mean.
ReplyDeleteyes, that value is excellent. anything around 12 and then that multiples the epsilon_o.
ReplyDeleteWell you are right that is not that realistic. The valence band is usually narrower and has a higher density of states than the conduction band (because the atomic state that makes the valence state does not extend out as far as the higher energy conduction band state).
ReplyDeleteHowever, for the n-p junction it makes the math simpler and easier if we make the valence band and conduction band DOS the same. Then the curvature of V(x) on the right sort of mirrors that on the left. So I thought it was a good idea to set them equal. It prioritizes simplicity over a more accurate representation.
(I think once you understand this simpler pn junction, you will have a sense of how one would generalize it to case where the Ds are different and where also the doping is not the same on both sides.)
For 4 a) im confused on how to do the charge density calculation given a distance in nm when the doping is given in units of cm^3. Could we assume that the semiconductor is a square to get a volume element of (100 nm)^3?
ReplyDeleteactually nevermind, that would only be needed to calculate the exact amount of charge, not the density
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ReplyDeleteI think he means this one:
ReplyDelete$$ n \approx kTD_{c}e^{-\frac{E_{c}-E_{f}}{kT}}$$
Though I personally don't know how would you use that approximation considering that $E_{f}$ isn't given.
ReplyDeleteAs a side note, is it possible to display in line text on MathJax in the comments Zack? I think this may be useful:
ReplyDeletehttp://tex.stackexchange.com/questions/13865/how-to-use-latex-on-blogspot
Actually, this may be a good approximation:
ReplyDelete$$ E_{f} = \frac{E_{c} + E_{v} + kTln(\frac{D_{v}}{D_{c}})}{2} $$
I just realized that this is very similar to one of the last homework problems
ReplyDeleteI wish I can really upvote this comment. I was jumping for joy to get a value of the halfway point between the valance and conduction band.
ReplyDeleteFor problem 1b, what do I do with the doping rate? It seems that I let n to be the doping rate just so I can get units of energy from the equation to get the Fermi-energy.
ReplyDeleteCan confirm.
DeleteSince we did not get to cover much about what happens when a voltage is applied to the junction, do we skip #8 &9 or will you make the homework due Wednesday, Zack?
ReplyDelete8 and 9 are pretty qualitative. You can do those this week. It is a good warm-up exercise. (I was not expecting to get to that at all in class; I think you can do those on your own (or discuss here if you are stuck.)
DeleteWhat we do next week with applied voltage will be much more technical and difficult.
Ok thanks.
DeleteFrom the conduction band. The net charge is all you had were holes.
ReplyDeleteWell yeah that is what you should assume, because all we really care is electrons in the conduction band. Besides there is no way you could calculate how many electrons there are in the lattice. All we know is how many more are being added by the donors. Hope that helps.
ReplyDeleteIt is an graph. An easy graph, as you say. no tricks.
ReplyDeleteRight. It is sort of just a mental exercise. Trying different values. But there is only one correct value that makes the system in equilibrium, as you say. Thanks.
ReplyDeleteFor problem 6, should the new doping be 10^19 instead of 10^18? Since X_d is proportional to 1/sqrt(N_d), wouldn't it take an increase by a factor of 100 in the doping to a see a decrease by a factor of 10 in the depletion width?
ReplyDeleteThese are good comments. Too late for me to change it now, but I think what you are saying makes a lot of sense.
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